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15x^2-6x-2160=0
a = 15; b = -6; c = -2160;
Δ = b2-4ac
Δ = -62-4·15·(-2160)
Δ = 129636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{129636}=\sqrt{36*3601}=\sqrt{36}*\sqrt{3601}=6\sqrt{3601}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{3601}}{2*15}=\frac{6-6\sqrt{3601}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{3601}}{2*15}=\frac{6+6\sqrt{3601}}{30} $
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